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Full Version: Wordlist numeric mangling question
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Assuming it's possible, how would one do the following given the wordlist below:

example wordlist:
password1
apple78

Given another wordlist or parameter with sequence 0-100, can oclHashcat dynamically generate the following passwords to try against hashes?

password0-100 (ie. password0, password1, password2, ... password100)
apple0-100 (ie. apple0, apple1, apple2, ... apple100)

So in other words, if the word in the wordlist already has a number on the end of it, oclhashcat would substitute that number with the numeric sequence provided and try every sequence. If the word in the wordlist doesn't end in a number, oclhashcat would ignore it. Another sequence example would be years (2000-2016)

password2000-2016 (ie. password2000, password2001, password2002, ... password2016)
etc...

Is this possible with oclhashcat?
No, this is not possible. Instead strip your wordlist down to basewords and do hybrid attacks.
i wrote a simple rule to do the first part where you start substituting alternative digits to find variances on existing bases with simple swaps, but you would need to expand on it to do the full sets you outlined above or follow epixoip's advice.

digit_expander.rule
Code:
## rule: digits expander
## limits: none
## example: john0 ---> john1, john2, john3, john4, ...

s01
s02
s03
s04
s05
s06
s07
s08
s09
s10
s12
s13
s14
s14
s15
s16
s17
s18
s19
s20
s21
s23
s24
s25
s26
s27
s28
s29
s30
s31
s32
s34
s35
s36
s37
s38
s39
s40
s41
s42
s43
s45
s46
s47
s48
s49
s50
s51
s52
s53
s54
s56
s57
s58
s59
s60
s61
s62
s63
s64
s65
s67
s68
s69
s70
s71
s72
s73
s74
s75
s76
s78
s79
s80
s81
s82
s83
s84
s85
s86
s87
s89
s90
s91
s92
s93
s94
s95
s96
s97
s98
s99

Hope that helps