01-17-2021, 05:59 PM
So, as I thought I found part of my password in a text file with the comment being way too cryptic for the second part .. yay me, well
Done in 2012!
Now.. I know for a fact that the password isn’t straight up with repetitive characters.
The first part is 4X8dRu , extrapolating myself here I am assuming it continues along the lines of randomness, no special characters.
I am asking for help to write a rule set that takes whatever maskprocessor pipes in and makes sure the same character is always only twice maximum in the whole password , must contain a number, a lower case an, uppercase all others are discarded.
So I was gonna do with with reject rule.. but because reject rules need 2 sides, I was thinking this:
mp64.bin -q2 -1?u?l?d ?1?1?1?1?1?1 | hashcat -m 15700 -a 1 hashther.hash -k reject.rule basepasswd.txt -
That basepassword contains the part of the password I know. This SHOULD work but the rule is a mystery to me still..
Yes this is an ether wallet and yes it will take years otherwise...so I am trying to narrow it down.. I am missing 6 characters.
Help?
Done in 2012!
Now.. I know for a fact that the password isn’t straight up with repetitive characters.
The first part is 4X8dRu , extrapolating myself here I am assuming it continues along the lines of randomness, no special characters.
I am asking for help to write a rule set that takes whatever maskprocessor pipes in and makes sure the same character is always only twice maximum in the whole password , must contain a number, a lower case an, uppercase all others are discarded.
So I was gonna do with with reject rule.. but because reject rules need 2 sides, I was thinking this:
mp64.bin -q2 -1?u?l?d ?1?1?1?1?1?1 | hashcat -m 15700 -a 1 hashther.hash -k reject.rule basepasswd.txt -
That basepassword contains the part of the password I know. This SHOULD work but the rule is a mystery to me still..
Yes this is an ether wallet and yes it will take years otherwise...so I am trying to narrow it down.. I am missing 6 characters.
Help?