How to do a real-brute-force ? - Printable Version +- hashcat Forum (https://hashcat.net/forum) +-- Forum: Deprecated; Previous versions (https://hashcat.net/forum/forum-29.html) +--- Forum: Old oclHashcat Support (https://hashcat.net/forum/forum-38.html) +--- Thread: How to do a real-brute-force ? (/thread-4606.html) |
How to do a real-brute-force ? - omegear - 08-14-2015 How to do a full brute-force operation ? I think the password is 9 characters-long but I'm not sure so masking is a bit useless for me. Code: cudaHashcat64.exe -a 3 -m 400 -i --increment-min=3 --increment-max=12 hash.txt ^This does a full lower-case alphabet brute-force from 3 to 12 character lenght, right ? RE: How to do a real-brute-force ? - epixoip - 08-14-2015 No. You're not specifying a mask, so it's using the builtin mask as documented on the wiki: http://hashcat.net/wiki/doku.php?id=oclhashcat#default_values To do a "full lower-case alphabet brute-force from 3 to 12 character" you'd add the mask "?l?l?l?l?l?l?l?l?l?l?l?l" to your current command. To do a "full brute-force operation" with all possible characters you'd use the "?a" builtin character class instead of "?l". |