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+--- Thread: Custom mask - brute force 12 length passwords with 1 capital letter, 1 number (/thread-8576.html)
Custom mask - brute force 12 length passwords with 1 capital letter, 1 number - asters - 08-18-2019
I need to use brute force to crack the password. I know about the password that it has exactly 1 capital letter (A-Z), exacly 1 number (1-9) and exacly 10 lowercase letters (from a to z).
I have Python script that generates this type of passwords, but I don't know how to turn it into a hashcat mask.
Code:
import random
random.seed(None)
lowers = 'qwertyuiopasdfghjklzxcvbnm'
uppers = 'QWERTYUIOPASDFGHJKLZXCVBNM'
number = '0123456789'
length = 12
while True:
uprspot = random.randint(0, length-1)
numspot = uprspot
while uprspot == numspot:
numspot = random.randint(0, length-1)
strgen = ""
for i in range (0, length):
if i == uprspot:
strgen += random.choice(uppers)
elif i == numspot:
strgen += random.choice(number)
else:
strgen += random.choice(lowers)
print(strgen)RE: Custom mask - brute force 12 length passwords with 1 capital letter, 1 number - royce - 08-18-2019
There's no single mask. You have to generate a *list of masks*.
You can do this with policygen from the PACK toolkit.
https://security.stackexchange.com/questions/158956/bruteforce-with-hashcat-how-to-set-the-mask-properly
RE: Custom mask - brute force 12 length passwords with 1 capital letter, 1 number - Ar76 - 08-19-2019
Still going to take a long time.