multiple characters in generated password - Printable Version +- hashcat Forum (https://hashcat.net/forum) +-- Forum: Misc (https://hashcat.net/forum/forum-15.html) +--- Forum: General Talk (https://hashcat.net/forum/forum-33.html) +--- Thread: multiple characters in generated password (/thread-9723.html) |
multiple characters in generated password - Katarnkyle - 12-26-2020 Is there any way how to tell maskprocessor or stdout function in hashcat to skip all the generated passwords with 3 or more same characters in a row ? Like " aaaaaa ; aaaaab, Bhzzzf ; !!!!!! ; aaaHcs " Or how to sort them out from already generated wordlist ? RE: multiple characters in generated password - hblender - 12-26-2020 Applying a rule could be an option. This site explains how to do it: https://hashcat.net/wiki/doku.php?id=rule_based_attack . That being said, I may be wrong, but there is no reject rule that rejects passwords that has repeated characters. The most similar reject rule that is aviable is %NX which "Reject plains which contain char X less than N times". From what I understood, it rejects passwords that contain e.g. if %4a it will reject aaar45gU9 ; 8YnjaaKw3 and so on. Now, if you already have a wordlist you could just open it in a text editor, like Notepad++ (I just tried with this one) and find "aaa ; bbb ; ccc ; ddd ; eee ; AAA ; BBB ; CCC ; DDD ; EEE ; 444 ;..." and delete the repeated characters. It may sound tedious, but it's the only way I've found right now. RE: multiple characters in generated password - hblender - 12-27-2020 GOT IT! Try using the maskprocessor. You will need to use the -q option: "Maximum number of multiple sequential characters" here's the link: https://github.com/hashcat/maskprocessor |