WPA 10 digit phone number using area code dictionary and 7 digit mask? HOW?
#1
Hi,
I am very new as this will illustrate.

Using ocl hashcat on ubuntu server 12.04 with Gnome
hashcat version 3.10
(4) amd HD5830 cards (so far)

Strictly WPA security testing here:

using something like:  .hc  -m2500 -a3 [hccap_file] ?d?d?d?d?d?d?d?d?d?d
This works but takes 4 days to run through 10^10 combinations (144kH/s) with overclock

I found this in an old forum
meow -m2500 -a3 [hccap_file] 707?d?d?d?d?d?d?d

Thats only aprox 30 min.

The problem is there are 387 area codes in the usa
I was hoping I could combine a rule and very small dictionary of the area codes (387) 3 digit numbers

tried this:  .hc  -m2500 -a3 [hccap_file] areacode.txt ?d?d?d?d?d?d?d (I don't have my notes in front of me but you get the idea. I think it worked but I got the message that the dictionary was to small and work load insufficient so
cards were throttled back to almost nothing. e.g. 137 days.. only 1 card runs, at aprox 40 H/s  (so basically nothing)

I tried something like .hc  -m2500 -a0 [hccap_file] ?d?d?d?d?d?d?d -r prepend_areacode.rule
where prepend_areacode. rule is:

^201
^202
^203
etc    387 area codes

That does not work because rules are only for dictionary attacks..
I also now realize it would be something like
^1^0^2
^2^0^2
^3^0^2
etc..

I think I also tried -a7 with no luck, i think that is left or right side of dictionary?

Any ideas? I have searched the forum I cannot believe i am the only person who has tried this..
using a dictionary attack of 387 area codes changes the combination from 10^10 or 10billion to 387x(10^7) or 3.8 billion

Thanks!


Messages In This Thread
WPA 10 digit phone number using area code dictionary and 7 digit mask? HOW? - by ICONOCLAST - 10-20-2016, 09:08 PM