if the password is more than 7 character, how do i find the other half? i created an LM hash of the word "password" but missing the "d" at the end once found, even though i specified mask of 8 char, it limits to 7 char.
./oclHashcat-lite64.bin -m 3000 e52cac67419a9a224a3b108f3fa6cb6d -1 ?l ?1?1?1?1?1?1?1?1
e52cac67419a9a224a3b108f3fa6cb6dASSWOR
Status.......: Cracked
Hash.Target..: e52cac67419a9a224a3b108f3fa6cb6d
Hash.Type....: LM
Time.Running.: 6 secs
Time.Left....: 0 secs
Plain.Mask...: ?1?1?1?1?1?1?1
Plain.Text...: ***ECSC
Plain.Length.: 7
Progress.....: 5839630976/8031810176 (72.71%)
./oclHashcat-lite64.bin -m 3000 e52cac67419a9a224a3b108f3fa6cb6d -1 ?l ?1?1?1?1?1?1?1?1
e52cac67419a9a224a3b108f3fa6cb6dASSWOR
Status.......: Cracked
Hash.Target..: e52cac67419a9a224a3b108f3fa6cb6d
Hash.Type....: LM
Time.Running.: 6 secs
Time.Left....: 0 secs
Plain.Mask...: ?1?1?1?1?1?1?1
Plain.Text...: ***ECSC
Plain.Length.: 7
Progress.....: 5839630976/8031810176 (72.71%)