Hi,
I try to find a preimage of a crypt(3) aka "descrypt" hash. I did a bruteforce of 1-8 char length with all 95 printable ASCII characters, but no luck. I now assume that the password consists of non-printable characters, too.
While the mask:
searches from 0x00 to 0xFF (256 values) I only need 0x00 to 0x7F (128 values) as crypt(3) is limited to this keyspace.
https://linux.die.net/man/3/crypt
How to build such a charset? Currently, my crypt3.hcchr looks like this, is it correct?
(A single line, no line breaks at the end)
I start hashcat like this
I try to find a preimage of a crypt(3) aka "descrypt" hash. I did a bruteforce of 1-8 char length with all 95 printable ASCII characters, but no luck. I now assume that the password consists of non-printable characters, too.
While the mask:
Code:
?b?b?b?b?b?b?b?bsearches from 0x00 to 0xFF (256 values) I only need 0x00 to 0x7F (128 values) as crypt(3) is limited to this keyspace.
https://linux.die.net/man/3/crypt
How to build such a charset? Currently, my crypt3.hcchr looks like this, is it correct?
Code:
user@pc:~# cat crypt3.hcchr
000102030405060708090A0B0C0D0E0F101112131415161718191A1B1C1D1E1F202122232425262728292A2B2C2D2E2F303132333435363738393A3B3C3D3E3F404142434445464748494A4B4C4D4E4F505152535455565758595A5B5C5D5E5F606162636465666768696A6B6C6D6E6F707172737475767778797A7B7C7D7E7F(A single line, no line breaks at the end)
I start hashcat like this
Code:
./hashcat64.bin -a 3 -m 1500 --session=mysession myhash.lst --hex-charset --custom-charset1=charsets/crypt3.hcchr masks/mymask.hcmask -o found.cracked