12-05-2021, 02:49 PM
(12-05-2021, 02:43 PM)penguinkeeper Wrote: Let's say 6 dict words, with 3 variations, that'd be 18 possible words per space, which would be 18^16, which is 121 quintillion, which is still way, way too high of a keyspace, even if you did have the tools
Again, I'm asking a general question about a preprocessing tool, not about the reality of running such an attack or its keyspace. It's actually a lot smaller since some words have less variations. Most words will have 5-6 variations in total, a few words will also have some capitilization variations on top of that. Thanks for the calculations.