hashcat
advanced password recovery

I have a hash file named hashcr.txt contain two hashalts vbb4:

Quote:<removed>
<removed

My command is:

Quote:root@server:~/Desktop/hashcat-0.40# ./hashcat-cli32.bin -m2711 -a0 /root/Desktop/hashcr.txt /root//dict/

And it retrun the result:

Quote:Initializing hashcat v0.40 by atom with 8 threads and 32mb segment-size...

NOTE: press enter for status-screen

Skipping line: <removed> (salt length exception)
1 salts contain seperator-char ':'
Added hashes from file /root/Desktop/hashcr.txt: 1 (1 salts)
Activating quick-digest mode for single-hash with salt
Input.Mode: Dict (/root//dict/0...9999999.dic)

Question 1: why this skipping line and add 1 hash?

Question 2: i want to bruteforce that password from 0 to 10 char and char from a -> z.
i use this command:

Quote:root@server:~/Desktop/hashcat-0.40# ./hashcat-cli32.bin -m2711 -a3 --pw-min=0 --pw-max=10 -o /root/Desktop/hashcr.txt.out /root/Desktop/hashcr.txt ?l

The result:

Quote:Initializing hashcat v0.40 by atom with 8 threads and 32mb segment-size...

NOTE: press enter for status-screen

Skipping line: <removed> (salt length exception)
1 salts contain seperator-char ':'
Added hashes from file /root/Desktop/hashcr.txt: 1 (1 salts)
Activating quick-digest mode for single-hash with salt
Input.Mode: Mask ()
Index.....: 0/1 (segment), 1 (words), 0 (bytes)
Recovered.: 0/1 hashes, 0/1 salts
Speed/sec.: - plains, - words
Progress..: 1/1 (100.00%)
Running...: --:--:--:--
Estimated.: --:--:--:--
Input.Mode: Mask (?l)
Index.....: 0/1 (segment), 26 (words), 0 (bytes)
Recovered.: 0/1 hashes, 0/1 salts
Speed/sec.: - plains, - words
Progress..: 26/26 (100.00%)
Running...: --:--:--:--
Estimated.: --:--:--:--
Started: Mon Aug 20 19:15:04 2012
Stopped: Mon Aug 20 19:15:04 2012

It stopped after start. Does my command is true?
anybody can helpme slove my problem.

Thank for read.
Sorry, my English is bad!

1. because you are an incompetent scripting kiddy.
2. the mask has to be at least the length to be bruteforced at maximum, say 10 times ?l for a 10 char password

Your salt is too long (35-char) BECAUSE there's HTML codes:
QFt`K&amp;t,t*EFQv*8*WT&amp;||Qg%nM
&amp; = &
Correct salt:QFt`K&t,t*EFQv*8*WT&||Qg%nM

Still, 27-char as a vBulletin doesn't seem right.

Thank undeath and M@LIK, I must to learn by English, hacking, encoding,... by myself. so you said that I'm a script kiddies is true.

Thank again. i'll learn more...and ask more... ^^
Greet!

(08-20-2012, 09:04 PM)xuanruou Wrote: Thank undeath and M@LIK, I must to learn by English, hacking, encoding,... by myself. so you said that I'm a script kiddies is true.

Thank again. i'll learn more...and ask more... ^^
Greet!

Well, it wont be for some time while I lock your account and provide ample time for you to read the posting rules.