Single symbol in random position with Brute-Force attack
#1
I've been trying to look for options to generate lowercase, uppercase, digits and a single symbol in a random position within 8 characters of length. The only command I can think of is
Code:
[b]hashcat -a 3 -m[hashmode] [hash] -1 ?l?u?d ?1?1?1?1?1?1?1?s[/b]
and then just switching every ?1 mask for a ?s in every position.
Would hashcat be able to do this in just a single command for every possible combination?
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#2
i this case i would say you should use a maskfile with 8 lines like you said

?l?u?d,?s,?1?1?1?1?1?1?1?2
?l?u?d,?s,?1?1?1?1?1?1?2?1

or

?l?u?d,?1?1?1?1?1?1?1?s
?l?u?d,?1?1?1?1?1?1?s?1


and so on, then use this maskfile instead of your singlemask on commandlin
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#3
(02-28-2021, 11:46 PM)Snoopy Wrote: i this case i would say you should use a maskfile with 8 lines like you said

?l?u?d,?s,?1?1?1?1?1?1?1?2
?l?u?d,?s,?1?1?1?1?1?1?2?1

or

?l?u?d,?1?1?1?1?1?1?1?s
?l?u?d,?1?1?1?1?1?1?s?1


and so on, then use this maskfile instead of your singlemask on commandlin

Oh, I didn't know you could put different masks into a file.
Thanks!
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