Missing partial password chunk in LM cracking
#7
i need something to reproduce, otherwise i cant fix it (if there is anything to fix).

yes, ?u will be translated into ?l and if both exists, it will get "merged", so the charset stays at 26 even if you do -1 ?l?u


Messages In This Thread
RE: Missing partial password chunk in LM cracking - by atom - 02-08-2012, 04:42 PM
RE: LM hash support for OCLHC - by chort - 02-07-2012, 09:50 AM