SHA512_HMAC
#2
Found the issue

seems like byte order is different for the output

my quick'n'dirty solution was to convert to uchar array after every iteration

Code:
for (int i=0; i<8; i++) { U[i*8] = (ctx0.opad.h[i] & 0xFF00000000000000) >> 56; U[i*8+1] = (ctx0.opad.h[i] & 0x00FF000000000000) >> 48; U[i*8+2] = (ctx0.opad.h[i] & 0x0000FF0000000000) >> 40; U[i*8+3] = (ctx0.opad.h[i] & 0x000000FF00000000) >> 32; U[i*8+4] = (ctx0.opad.h[i] & 0x00000000FF000000) >> 24; U[i*8+5] = (ctx0.opad.h[i] & 0x0000000000FF0000) >> 16; U[i*8+6] = (ctx0.opad.h[i] & 0x000000000000FF00) >> 8; U[i*8+7] = ctx0.opad.h[i] & 0x00000000000000FF; }

would still be interested to know if am mis-using the API, and if there are better fixes.
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Messages In This Thread
SHA512_HMAC - by ruro - 12-05-2020, 07:40 PM
RE: SHA512_HMAC - by ruro - 12-06-2020, 02:45 PM