10-15-2022, 12:15 PM
You use the attack-mode "-a 3", which expects a mask.
You specify your mask by typing 18 times ?d in your command, so you give the instruction to Hashcat to use a 18-long-digits mask.
Now, since you only want to try from 8 till 15 digits without each time manually needing to change the command, one can use the "--increment" with min and a max.
Some suggestions to clean-up your command:
- why do you use the custom mask "-1 ?d"; it's pointless because your mask does not contain ?1 but only ?d
- hashcat rejects automatically for -m 22000 everything below 8 char; so the increment-min is not necessary
This would be my suggestion in order to crack from 8 till 15 chars:
You specify your mask by typing 18 times ?d in your command, so you give the instruction to Hashcat to use a 18-long-digits mask.
Now, since you only want to try from 8 till 15 digits without each time manually needing to change the command, one can use the "--increment" with min and a max.
Some suggestions to clean-up your command:
- why do you use the custom mask "-1 ?d"; it's pointless because your mask does not contain ?1 but only ?d
- hashcat rejects automatically for -m 22000 everything below 8 char; so the increment-min is not necessary
This would be my suggestion in order to crack from 8 till 15 chars:
Code:
hashcat.exe -m 22000 hash.22000 -a 3 ?d?d?d?d?d?d?d?d?d?d?d?d?d?d?d -i