new module: md5 with substitution
#2
anyone an idea?



how to brute force such a hash with all alphanumeric 6 char strings?



example with 3 char only:



Code:
hash('foo') = md5(subs['f']+subs['o']+subs['o'])
            = md5('gdf4oiu8gugu3otyu081rtyu3otyu081rty') = '2144e74661812f17e37f972c981282d9'


thanks!
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Messages In This Thread
new module: md5 with substitution - by phaphip - 05-09-2022, 07:22 PM
RE: new module: md5 with substitution - by phaphip - 05-13-2022, 09:27 AM