07-22-2022, 08:34 AM
I want to crack a VeraCrypt SHA512 + XTS 1536 bit encryption with the latest hashcat beta. According to the example hashes the hash mode should be 29423.
The example hash looks like this:
So this time it is not the first 512 bytes of a veracrypt encrypted volume/device but a "real hash string". I did not found anything about this syntax in the hashcat documentation/wiki. How can i obtain this 1024 byte string?
The example hash looks like this:
Code:
$veracrypt$d44f26d1742260f88023d825729cc5a64cf8475d887632a2fb4a84af27af138cfadc4bcbb122f6ba68339ae8427d1f72c0c4aeef041291492ae0a7d8677d8da4$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
So this time it is not the first 512 bytes of a veracrypt encrypted volume/device but a "real hash string". I did not found anything about this syntax in the hashcat documentation/wiki. How can i obtain this 1024 byte string?