Character Set question

[Technodude_UK]

Hi.  I'm pretty new to Hashcat so apologies if this is a stupid question.

[*]I've got a long, complex password I want to crack but I know it doesn't include all of the characters from the built-in charsets.
[*]For example...  I need all of ?l and ?u but only the number 1 and only a % symbol.  I've been using ?a but figured I can reduce the combinations needed by a few billion if I can drop unnecessary characters...


[*]

• ?l = abcdefghijklmnopqrstuvwxyz
  
• ?u = ABCDEFGHIJKLMNOPQRSTUVWXYZ
  
• ?d = 0123456789
  
• ?s = «space»!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
  

[*]Is there an easy way to create a reduced charset including only those I need please?

[buka]

Yes. In the command line,

-1 ?l?u1% ?1?1?1?1?1?1?1?1?1

Or, in the mask file,

?l?u1%,?1?1?1?1?1?1?1?1?1