Generating a SHA256 Hash from another Hash
Xsample is under the ill impression that someone would crack each step of an iterated hash separately.

here's the pseudo-code of how hash cracking really works:
for candidate in candidate_list:
   if hash_algo(candidate) == searched_hash:
       return candidate

hash_algo is completely exchangeable and it does not matter if this is SHA1, SHA512, 10x SHA512 or PBKDF2-SHA512
Ooh now I get it, well yeah I guess the answer to that was already provided.