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How do the characters of a password get clipped or altered to conform to the 7bit input for DES characters? When i use maskprocessor with -1=?l?u?d?s?D?F?R ?1 i get 143 different characters, yet if DES is only using 7bits then there is a maximum 128 possible options.
I would like to create a rule to append every possible character to the end of a wordlist, without duplicates.
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(11-30-2011, 08:57 PM)PHloGiSTo Wrote: How do the characters of a password get clipped or altered to conform to the 7bit input for DES characters? When i use maskprocessor with -1=?l?u?d?s?D?F?R ?1 i get 143 different characters, yet if DES is only using 7bits then there is a maximum 128 possible options.
DES algorithm shifts each char 1 bit to the left (8 - 1 = 7). For example, german ö (oe) encoded as 8 bit iso-8859-1 is 0xf6 (11110110), shifting it one to the left results in (11101100), which is the same result as the input 0x76 would result. in other words its converted to "v".
(11-30-2011, 08:57 PM)PHloGiSTo Wrote: I would like to create a rule to append every possible character to the end of a wordlist, without duplicates.
how is this related to 7bit keys?
