Problem with sha-256 crack

[Shirakumo]

Hello, I'm new with hashcat and the teacher showed it to us last week during the class. He sent us a tip to later decoding of ase-128 but the tip is coded by sha-256.

What I know about the password: length - 14, first 6 characters are numbers or big letters, another 2 are special characters and the last 6 are numbers or small or big letters. So, my command looks like: sudo ./hashcat64.bin -m1400 -a3 -1?u?d -2?s -3?l?u?d hash.txt  ?1?1?1?1?1?1?2?2?3?3?3?3?3?3 -o wynik.txt (hash.txt is a file where I have a hash and wynik.txt is a file when I want the program to write the result).

During running this command I'm getting a message: " Integer overflow detected in keyspace of mask: ?1?1?1?1?1?1?2?2?3?3?3?3?3?3. I have read a bit about this attack and couldn't find sure answer whether it's possible to crack such long password. Anyone can help?

Cheers

[undeath]

that's way too many possibilities

[Shirakumo]

So you mean that even if such knowledge about password I'm not able to crack it in rational time?

[undeath]

that's a basic math problem, calculate yourself

[plaverty9]

This seems relevant to what you're dealing with: https://github.com/hashcat/hashcat/issues/1467

[Shirakumo]

I have seen that. Ok, so if it is not possible to solve then I will give up with it. Maybe our teacher knew that it can't be solved. Thank you guys

[plaverty9]

I think what undeath was trying to say is "yes", it'll take a long time. Look at what it's trying to guess:

First six have a keyspace of 36 each
Next two have a keyspace of 33 each
Last six have a keyspace of 62 each

Just the first six have 1.0314425e+28 possibilities
This also seems relevant: https://hashcat.net/forum/thread-7035.html