10-01-2016, 10:48 PM
@atom Thanks for your reply!
Here are some of the duplicates from rules/T0XlCv1.rule ( complete list: here ):
perl duprule.pl < ../hashcat/rules/T0XlCv1.rule
1. ^a^i^d, i0d i1i i2a
2. x32, x32+2
3. :, tt
4. D2 D2, D3D2
5. '3d, x03d
6. *22se3, se3
7. x31Y3i7&i5vL9'4, x31
8. ] { [ }, D1], ],1[
Explanation:
1. ^a^i^d will have this change on map:
- push elements with characters 'a', then 'i', then 'd' to the start of the word
i0d i1i i2a
- insert element with character 'd' at position 0, 'i' at position 1, 'a' at position 2.
2. x32
- from position 3, take two characters, so the map will be reduced to these two characters
x32+2
- as above, but increase character at position 2 ( character number 3 ) by 1 ascii value. As the third character doesn't exist they are duplicates.
3. :
- change nothing.
tt
- the first 't' will toggle all the cases, 'u' -> 'l', 'l' -> 'u', 'd' ( default, unknown case ) -> 'b' ( the opposed case of 'd' ), and the second 't' will toggle all the cases back. That's why it's duplicate with :.
4. D2 D2
- Delete element at position 2, then with the new word, delete element at position 2 ( it was the third element )
D3D2
- Delete element at position 3, then delete the element at position 2.
5. 'n have the same effect as x0n.
6. *nn will swap position n with position n, so nothing will happen.
7. x31 will take 1 character from position 0, so all changes on elements with position > 0 will have no effects.
8.
] { [ }
- Delete last element.
- rotate word left.
- Delete element at position 0 ( it's old position was 1 ).
- rotate work right.
D1]
- Delete element at position 1.
- Delete last element.
],1[
- Delete last element.
- Replace element at position 1 with element at position 0
- Delete element at position 0.
For more examples, please have a look at this test, and this test will give an overview over the map.
Here are some of the duplicates from rules/T0XlCv1.rule ( complete list: here ):
perl duprule.pl < ../hashcat/rules/T0XlCv1.rule
1. ^a^i^d, i0d i1i i2a
2. x32, x32+2
3. :, tt
4. D2 D2, D3D2
5. '3d, x03d
6. *22se3, se3
7. x31Y3i7&i5vL9'4, x31
8. ] { [ }, D1], ],1[
Explanation:
1. ^a^i^d will have this change on map:
- push elements with characters 'a', then 'i', then 'd' to the start of the word
i0d i1i i2a
- insert element with character 'd' at position 0, 'i' at position 1, 'a' at position 2.
2. x32
- from position 3, take two characters, so the map will be reduced to these two characters
x32+2
- as above, but increase character at position 2 ( character number 3 ) by 1 ascii value. As the third character doesn't exist they are duplicates.
3. :
- change nothing.
tt
- the first 't' will toggle all the cases, 'u' -> 'l', 'l' -> 'u', 'd' ( default, unknown case ) -> 'b' ( the opposed case of 'd' ), and the second 't' will toggle all the cases back. That's why it's duplicate with :.
4. D2 D2
- Delete element at position 2, then with the new word, delete element at position 2 ( it was the third element )
D3D2
- Delete element at position 3, then delete the element at position 2.
5. 'n have the same effect as x0n.
6. *nn will swap position n with position n, so nothing will happen.
7. x31 will take 1 character from position 0, so all changes on elements with position > 0 will have no effects.
8.
] { [ }
- Delete last element.
- rotate word left.
- Delete element at position 0 ( it's old position was 1 ).
- rotate work right.
D1]
- Delete element at position 1.
- Delete last element.
],1[
- Delete last element.
- Replace element at position 1 with element at position 0
- Delete element at position 0.
For more examples, please have a look at this test, and this test will give an overview over the map.