first i dont understand what your link has to do with your question, is this advertising? if so please remove.
the hash consists of multiple parts with some built in safety checks, so hashcat should recognize whether or not your hash "seems" okay
take a look at at the example hash and the source for modlule 11300 at github (following is the examples hash splittet by $)
the two 96, the 16 and the 66 are the lenght of the following parts, so if your hash is "longer" this should reflect in these numbers, anyway as i said above, if hashcat accepts your hash, these safety checks are passed
the hash consists of multiple parts with some built in safety checks, so hashcat should recognize whether or not your hash "seems" okay
take a look at at the example hash and the source for modlule 11300 at github (following is the examples hash splittet by $)
Code:
bitcoin
96
d011a1b6a8d675b7a36d0cd2efaca32a9f8dc1d57d6d01a58399ea04e703e8bbb44899039326f7a00f171a7bbc854a54
16
1563277210780230
158555
96
628835426818227243334570448571536352510740823233055715845322741625407685873076027233865346542174
66
625882875480513751851333441623702852811440775888122046360561760525the two 96, the 16 and the 66 are the lenght of the following parts, so if your hash is "longer" this should reflect in these numbers, anyway as i said above, if hashcat accepts your hash, these safety checks are passed