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Hashcat with bitcoin2john.py - How many characters ?a?a..?

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Hashcat with bitcoin2john.py - How many characters ?a?a..?
realman123 Offline
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#1
06-29-2021, 11:19 PM (This post was last modified: 06-29-2021, 11:34 PM by realman123.)
Hello everybody,


Initially I asked a different thing in this topic but I solved it by just redoing the whole process, as I think my bitcoin2john.py file was empty at first.

Now my question is, when I enter the prompt like

hashcat64.exe -a 3 -m 11300 wallethash.txt ?a?a?a?a?a?a?a?a?a?a?a?a


The "?a" is one character, right? How many characters should I chose, if I cannot remember how many characters I used for the passphrase?

I would appreciate any support! Thx!
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Snoopy Offline
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#2
06-30-2021, 01:09 PM (This post was last modified: 06-30-2021, 01:13 PM by Snoopy.)
?a means all possible "standard chars" a-zA-Z0-9 and special chars like *# (see help)

well you can choose i think up to 12 times ?a before you ran into a buffer overflow, if you dont remember anything choose option --increment to tell hashcat to start at postition one with this mask and try upwards one, two three and so on positions ?a -> ?a?a -> ?a?a?a ...
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