Pls need advice on forging custom diclists
#1
What is the easiest way to do such operations :
1-pick all 8 chars long words from a list file and create a new one with them only.
2- append a couple predefined pre or suffix to these words (123, 111, 007 for example)

I would rather do this in a linux terminal but i dont mind using a windows gui app.

Thank you, any help is greatly appreciated.
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#2
http://unifiedlm.com/Features
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#3
(01-29-2017, 10:31 PM)heretolearn Wrote: What is the easiest way to do such operations :
1-pick all 8 chars long words from a list file and create a new one with them only.
2- append a couple predefined pre or suffix to these words (123, 111, 007 for example)

I would rather do this in a linux terminal but i dont mind using a  windows gui app.

Thank you, any help is greatly appreciated.

Check this out:
https://hashcat.net/wiki/doku.php?id=hashcat_utils#len

And this:
https://hashcat.net/wiki/doku.php?id=rule_based_attack

Or this:

cat your_dict.txt | awk 'length()==8' > new_dict.txt
for i in `cat new_dict.txt`; do echo ${i}123 >> new_dict123.txt; done

Google for other solutions.
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#4
UUoC! awk 'length == 8' dict1 > dict2

For the second one, a 'for' loop won't work if the wordlist has more lines than ARG_MAX or if the words contain spaces, plus UUoC again, so that would be a very poor solution. A 'while' loop would be better: while read word; do echo "${word}123"; done < dict2 >> dict3

Or, since this is Hashcat: ./hashcat --stdout -j '$1$2$3' dict2 >dict3

Personally I'd probably just use sed 's/$/123/' dict2 >dict3
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#5
Of course. This was just an example when no one was answering him.
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